Fermat 2024 Part B - Question 12, CEMC UWaterloo
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Difficulty: 4
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(Fermat 2024, Part B, Question 12, CEMC - UWaterloo)
The numbers $5$, $6$, $10$, $17$, and $21$ are rearranged so that the sum of the first three numbers is equal to the sum of the last three numbers. Which number is in the middle of this arrangement?
$(A)$ $5$
$(B)$ $6$
$(C)$ $10$
$(D)$ $17$
$(E)$ $21$
Answer Submission Note(s)
Your answer should be a single capital letter, e.g. 'A'.
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