POTW #25 - Oct. 7, 2024
Contributed by: bruhmoment
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Difficulty: 8
This problem is tagged with potw, potw2024.
MCR Problem of the Week, Oct. 7, 2024 Edition
In triangle $ABC$, $M$ is the midpoint of $BC$, and $D$ is the foot of the angle bisector from $A$. Given that $AM = BC = 26$ and $DM = 26/29$, find the area of triangle $ABC$ in the form $a \sqrt b$ such that $b$ is squarefree.
Answer Submission Note(s)
Type your answer in the form a*sqrt(b).
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